Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
3x4 – 2x3 + x + 8
Advertisements
उत्तर
Let y = 3x4 – 2x3 + x + 8
`"dy"/"dx" = "d"/"dx" (3x^4) - "d"/"dx" (2x^3) + "d"/"dx" (x) + "d"/"dx"(8)`
`= 3"d"/"dx" (x^4) - 2"d"/"dx" (x^3) + 1 + 0`
`= 3(4 * x^(4 - 1)) - 2(3x^(3-1)) + 1`
= 12x3 - 6x2 + 1
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`sqrtx + 1/root(3)(x) + e^x`
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
`e^x/(1 + e^x)`
If 4x + 3y = log(4x – 3y), then find `"dy"/"dx"`
Differentiate the following with respect to x.
(sin x)x
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Find `"dy"/"dx"` of the following function:
x = ct, y = `c/t`
Find y2 for the following function:
x = a cosθ, y = a sinθ
If y = `(x + sqrt(1 + x^2))^m`, then show that (1 + x2) y2 + xy1 – m2y = 0
If xy . yx , then prove that `"dy"/"dx" = y/x((x log y - y)/(y log x - x))`
