Advertisements
Advertisements
प्रश्न
Differentiate sin2x with respect to x2.
Advertisements
उत्तर
Let u = (sin x)2 ; v = x2
`"du"/"dx"` = (2 sin x) (cos x) = sin 2x ; `"dv"/"dx"` = 2x
`"du"/"dv" = ("du"/"dx")/("dv"/"dx") = (sin 2x)/(2x)`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`sqrtx + 1/root(3)(x) + e^x`
Differentiate the following with respect to x.
(x2 – 3x + 2) (x + 1)
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Differentiate the following with respect to x.
`e^x/(1 + e^x)`
Differentiate the following with respect to x.
cos3 x
Differentiate the following with respect to x.
sin(x2)
Find `"dy"/"dx"` of the following function:
x = a(θ – sin θ), y = a(1 – cos θ)
Find y2 for the following function:
y = log x + ax
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
