Advertisements
Advertisements
प्रश्न
Differentiate sin2x with respect to x2.
Advertisements
उत्तर
Let u = (sin x)2 ; v = x2
`"du"/"dx"` = (2 sin x) (cos x) = sin 2x ; `"dv"/"dx"` = 2x
`"du"/"dv" = ("du"/"dx")/("dv"/"dx") = (sin 2x)/(2x)`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
3x4 – 2x3 + x + 8
Differentiate the following with respect to x.
ex (x + log x)
Differentiate the following with respect to x.
cos3 x
Find `"dy"/"dx"` for the following function
xy – tan(xy)
If `xsqrt(1 + y) + ysqrt(1 + x)` = 0 and x ≠ y, then prove that `"dy"/"dx" = - 1/(x + 1)^2`
If 4x + 3y = log(4x – 3y), then find `"dy"/"dx"`
Find y2 for the following function:
y = e3x+2
If y = `(x + sqrt(1 + x^2))^m`, then show that (1 + x2) y2 + xy1 – m2y = 0
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
