Advertisements
Advertisements
प्रश्न
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
Advertisements
उत्तर
Let y = `(3 + 2x - x^2)/x`
`= 3/x + (2x)/x - x^2/x`
y = `3/x + 2 - x`
`"dy"/"dx" = (-3)/x^2 + 0 - 1`
`= (-3)/x^2 - 1`
`= (- 3 - x^2)/x^2`
`= - ((3 + x^2))/x^2`
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
x3 ex
Differentiate the following with respect to x.
(x2 – 3x + 2) (x + 1)
Differentiate the following with respect to x.
ex (x + log x)
Differentiate the following with respect to x.
(ax2 + bx + c)n
Differentiate the following with respect to x.
sin(x2)
Differentiate the following with respect to x.
xsin x
Differentiate the following with respect to x.
(sin x)tan x
Find `"dy"/"dx"` of the following function:
x = a cos3θ, y = a sin3θ
If xy . yx , then prove that `"dy"/"dx" = y/x((x log y - y)/(y log x - x))`
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
