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Question
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
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Solution
Let y = `(3 + 2x - x^2)/x`
`= 3/x + (2x)/x - x^2/x`
y = `3/x + 2 - x`
`"dy"/"dx" = (-3)/x^2 + 0 - 1`
`= (-3)/x^2 - 1`
`= (- 3 - x^2)/x^2`
`= - ((3 + x^2))/x^2`
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