Advertisements
Advertisements
Question
Differentiate the following with respect to x.
`sqrtx + 1/root(3)(x) + e^x`
Advertisements
Solution
Let y = `sqrtx + 1/root(3)(x) + e^x`
y = `x^(1/2) + x^(1/3) + e^x`
`[because 1/root(3)(x) = 1/(x^(1/3)) = x^(1/3)]`
`"dy"/"dx" = "d"/"dx" (x^(1/2)) + "d"/"dx" (x^(-1/3)) + "d"/"dx" (e^x)`
`= 1/2 x^(1/2 - 1) + ((- 1)/3) x^((-1)/3 - 1) + e^x`
`= 1/2 x^((-1)/2) - 1/3 1/(x^(4/3)) + e^x`
`= 1/2 1/(x^(1/2)) - 1/3 1/(x^(4/3)) + e^x`
`= 1/(2sqrtx) - 1/(3 root(3)(x^4)) + e^x`
APPEARS IN
RELATED QUESTIONS
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Differentiate the following with respect to x.
`e^x/(1 + x)`
Differentiate the following with respect to x.
x sin x
Differentiate the following with respect to x.
ex sin x
Differentiate the following with respect to x.
`sqrt(1 + x^2)`
Find `"dy"/"dx"` of the following function:
x = a cos3θ, y = a sin3θ
Differentiate sin3x with respect to cos3x.
If y = sin(log x), then show that x2y2 + xy1 + y = 0.
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
If y = 2 sin x + 3 cos x, then show that y2 + y = 0.
