Advertisements
Advertisements
प्रश्न
Differentiate sin3x with respect to cos3x.
Advertisements
उत्तर
Let u = sin3x = (sin x)3 ; v = cos3x = (cos x)3
`"du"/"dv" = ("du"/"dx")/("dv"/"dx")`
`= (3 sin^2x cos x)/(3 cos^2 x (- sin x))`
`= (- sin x)/(cos x)` = - tan x
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
(x2 – 3x + 2) (x + 1)
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
Differentiate the following with respect to x.
`e^x/(1 + x)`
Differentiate the following with respect to x.
sin x cos x
Differentiate the following with respect to x.
cos2 x
Differentiate the following with respect to x.
sin(x2)
Find `"dy"/"dx"` for the following function.
x3 + y3 + 3axy = 1
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
If y = 2 + log x, then show that xy2 + y1 = 0.
If y = sin(log x), then show that x2y2 + xy1 + y = 0.
