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प्रश्न
Differentiate sin3x with respect to cos3x.
योग
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उत्तर
Let u = sin3x = (sin x)3 ; v = cos3x = (cos x)3
`"du"/"dv" = ("du"/"dx")/("dv"/"dx")`
`= (3 sin^2x cos x)/(3 cos^2 x (- sin x))`
`= (- sin x)/(cos x)` = - tan x
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