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Karnataka Board PUCPUC Science Class 11

Figure Shows a Horizontal Solenoid Connected to a Battery and a Switch. a Copper Ring is Placed on a Frictionless Track, the Axis of the Ring Being Along the Axis of the Solenoid.

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Question

Figure shows a horizontal solenoid connected to a battery and a switch. A copper ring is placed on a frictionless track, the axis of the ring being along the axis of the solenoid. As the switch is closed, the ring will __________ .

Options

  • remain stationary

  • move towards the solenoid

  • move away from the solenoid

  • move towards the solenoid or away from it depending on which terminal (positive or negative) of the battery is connected to the left end of the solenoid

MCQ
Fill in the Blanks
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Solution

move away from the solenoid

 

For the circuit,

`E=-L(di)/(dt)`

The current will increase in the solenoid, flowing in clockwise direction in the circuit. Due to this increased current, the flux linked with the copper ring with increase with time, causing an induced current. This induced current will oppose the cause producing it. Hence, the current in the copper ring will be in anticlockwise direction. Now, because the directions of currents in the solenoid and ring are opposite, the ring will be repelled and hence will move away from the solenoid.

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Chapter 38: Electromagnetic Induction - MCQ [Page 304]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 38 Electromagnetic Induction
MCQ | Q 6 | Page 304

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