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Figure Shows a Horizontal Solenoid Connected to a Battery and a Switch. a Copper Ring is Placed on a Frictionless Track, the Axis of the Ring Being Along the Axis of the Solenoid. - Physics

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प्रश्न

Figure shows a horizontal solenoid connected to a battery and a switch. A copper ring is placed on a frictionless track, the axis of the ring being along the axis of the solenoid. As the switch is closed, the ring will __________ .

विकल्प

  • remain stationary

  • move towards the solenoid

  • move away from the solenoid

  • move towards the solenoid or away from it depending on which terminal (positive or negative) of the battery is connected to the left end of the solenoid

MCQ
रिक्त स्थान भरें
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उत्तर

move away from the solenoid

 

For the circuit,

`E=-L(di)/(dt)`

The current will increase in the solenoid, flowing in clockwise direction in the circuit. Due to this increased current, the flux linked with the copper ring with increase with time, causing an induced current. This induced current will oppose the cause producing it. Hence, the current in the copper ring will be in anticlockwise direction. Now, because the directions of currents in the solenoid and ring are opposite, the ring will be repelled and hence will move away from the solenoid.

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अध्याय 16: Electromagnetic Induction - MCQ [पृष्ठ ३०४]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 16 Electromagnetic Induction
MCQ | Q 6 | पृष्ठ ३०४

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