Question

Factorise the following by taking out the common factors:
2a(p² + q²) + 4b(p² + q²)

Answer 1

2a(p² + q²) + 4b(p² + q²)
Here, the common factor is 2(p² + q²)
Dividing throughtout by 2(p² + q²), we get

`(2"a"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)) + (4"b"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)`
= a + 2b
∴ 2a(p² + q²) + 4b(p² + q²)
= 2(p² + q²)(a + 2b).