Advertisements
Advertisements
प्रश्न
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
Advertisements
उत्तर
2a(p2 + q2) + 4b(p2 + q2)
Here, the common factor is 2(p2 + q2)
Dividing throughtout by 2(p2 + q2), we get
`(2"a"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)) + (4"b"("p"^2 + "q"^2))/(2("p"^2 + "q"^2)`
= a + 2b
∴ 2a(p2 + q2) + 4b(p2 + q2)
= 2(p2 + q2)(a + 2b).
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
6 abc, 24ab2, 12a2b
Find the common factors of the terms.
16x3, −4x2, 32x
Factorise the following expression:
7x − 42
Factorise the following expression:
7a2 + 14a
Factorise the following expression:
20 l2m + 30 alm
Factorise.
15xy − 6x + 5y − 2
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factorize the following:
−4a2 + 4ab − 4ca
Factorize the following:
ax2y + bxy2 + cxyz
Factorise : `x^2 + 1/x^2 - 3`
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Find the value of : ( 987 )2 - (13)2
Find the value of : ( 67.8 )2 - ( 32.2 )2
Factorise : 3x2 + 6x3
Factorise : 6x2y + 9xy2 + 4y3
Factorise : 12abc - 6a2b2c2 + 3a3b3c3
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
Factorise: 6xy(a2 + b2) + 8yz(a2 + b2) −10xz(a2 + b2)
factorise : 35a3b2c + 42ab2c2
factorise : a2 - ab - 3a + 3b
factorise : (ax + by)2 + (bx - ay)2
factorise : m - 1 - (m-1)2 + am - a
Factorise the following by taking out the common factors:
2x5y + 8x3y2 - 12x2y3
Factorise the following by taking out the common factors:
81(p + q)2 -9p - 9q
Factorise the following by taking out the common factors:
p(p2 + q2 - r2) + q(r2 - q2 -p2) - r(p2 + q2 - r2)
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise the following by taking out the common factor
18xy – 12yz
