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प्रश्न
Factorise: 6xy(a2 + b2) + 8yz(a2 + b2) −10xz(a2 + b2)
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उत्तर
6xy(a2 + b2) + 8yz(a2 + b2) − 10xz(a2 + b2)
Since (a2 + b2) is common in all three terms, factor it out:
(6xy + 8yz − 10xz)(a2 + b2)
Now the expression is:
(6xy + 8yz − 10xz)(a2 + b2)
Factorize the trinomial 6xy + 8yz − 10xz
6xy + 8yz − 10xz = 2y(3x + 4z) − 2z(5x).
y(3x + 4z) − 2z(5x) = 2(3x + 4z)(y − z).
The fully factorized form of the original expression is:
2(3x + 4z)(y − z)(a2 + b2)
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