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Question
Factorise the following expression:
− 4a2 + 4ab − 4 ca
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Solution
− 4a2 = −1 × 2 × 2 × a × a
4ab = 2 × 2 × a × b
− 4ca = −1 × 2 × 2 × c × a
The common factors are 2, 2, and a.
∴ − 4a2 + 4ab − 4ca
= −1 (2 × 2 × a × a) + (2 × 2 × a × b) −1 (2 × 2 × c × a)
= 2 × 2 × a [−1 (a) + b −1 × c]
= 4a (− a + b − c)
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