Advertisements
Advertisements
Question
Factorise the following expression:
10a2 − 15b2 + 20c2
Advertisements
Solution
10a2 = 2 × 5 × a × a
−15b2 = 3 × 5 × b × b
20c2 = 2 × 2 × 5 × c × c
The common factor is 5.
10a2 − 15b2 + 20c2
= (2 × 5 × a × a) − (3 × 5 × b × b) + (2 × 2 × 5 × c × c)
= 5 [(2 × a × a) − (3 × b × b) + (2 × 2 × c × c)]
= 5 (2a2 − 3b2 + 4c2)
APPEARS IN
RELATED QUESTIONS
Factorise the following expression:
−16z + 20z3
Factorise : `(9a)^2 + 1/(9a)^2 - 2 - 12a + 4/(3a)`
Factorise: x4 + y4 - 3x2y2
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Find the value of : ( 67.8 )2 - ( 32.2 )2
Find the value of : `[(18.5)^2 - (6.5)^2]/[18.5 + 6.5]`
Factorise the following by taking out the common factors:
4x2y3 - 6x3y2 - 12xy2
Factorise:
`"p"^2 + (1)/"p"^2 - 3`
Factorise:
5x2 - y2 - 4xy + 3x - 3y
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
