Advertisements
Advertisements
Question
Factorise the following expression:
10a2 − 15b2 + 20c2
Sum
Advertisements
Solution
10a2 = 2 × 5 × a × a
−15b2 = 3 × 5 × b × b
20c2 = 2 × 2 × 5 × c × c
The common factor is 5.
10a2 − 15b2 + 20c2
= (2 × 5 × a × a) − (3 × 5 × b × b) + (2 × 2 × 5 × c × c)
= 5 [(2 × a × a) − (3 × b × b) + (2 × 2 × c × c)]
= 5 (2a2 − 3b2 + 4c2)
shaalaa.com
Is there an error in this question or solution?
Chapter 12: Factorisation - EXERCISE 12.1 [Page 148]
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
14pq, 28p2q2
Factorise:
`x^4 + y^4 - 27x^2y^2`
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise: x4 + y4 - 3x2y2
Factorise : 3 - 5x + 5y - 12(x - y)2
Factorise : 2√3x2 + x - 5√3
factorise : 6x3 - 8x2
Factorise xy2 - xz2, Hence, find the value of :
9 x 82 - 9 x 22
Factorise the following by taking out the common factors:
12a3 + 15a2b - 21ab2
Factorise the following by taking out the common factors:
2a(p2 + q2) + 4b(p2 + q2)
