Advertisements
Advertisements
Question
Factorise : 17a6b8 - 34a4b6 + 51a2b4
Advertisements
Solution
17a6b8 - 34a4b6 + 51a2b4 = 17a2b4 (a4b4 - 2a2b2 + 3)
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
2y, 22xy
Find the common factors of the terms.
6 abc, 24ab2, 12a2b
Find the common factors of the terms.
10pq, 20qr, 30rp
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
2x3y2 − 4x2y3 + 8xy4
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Factorize the following:
28a2 + 14a2b2 − 21a4
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise:
(2a - 3)2 - 2 (2a - 3) (a - 1) + (a - 1)2
Factorise : 4(2x - 3y)2 - 8x+12y - 3
Factorise : 2(ab + cd) - a2 - b2 + c2 + d2
Factorise : 15x + 5
factorise : 35a3b2c + 42ab2c2
factorise : a2 - ab - 3a + 3b
factorise : xy2 + (x - 1) y - 1
Factorise the following by taking out the common factors:
81(p + q)2 -9p - 9q
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
