Advertisements
Advertisements
Question
Factorise : 17a6b8 - 34a4b6 + 51a2b4
Advertisements
Solution
17a6b8 - 34a4b6 + 51a2b4 = 17a2b4 (a4b4 - 2a2b2 + 3)
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
3x2y3, 10x3y2, 6x2y2z
Factorize the following:
20a12b2 − 15a8b4
Factorize the following:
28a2 + 14a2b2 − 21a4
Factorize the following:
16m − 4m2
Factorize the following:
−4a2 + 4ab − 4ca
Factorise:
`x^2 + 1/(4x^2) + 1 - 7x - 7/(2x)`
Factorise : (a2 - a) (4a2 - 4a - 5) - 6
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : 3 - 5x + 5y - 12(x - y)2
Find the value of : `[(18.5)^2 - (6.5)^2]/[18.5 + 6.5]`
Factorise : 3x5y - 27x4y2 + 12x3y3
Factorise : 4x(3x - 2y) - 2y(3x - 2y)
factorise : 6x3 - 8x2
Factorise: 36x2y2 - 30x3y3 + 48x3y2
factorise:
9a (x − 2y)4 − 12a (x − 2y)3
factorise : a2 - ab - 3a + 3b
factorise : x2y - xy2 + 5x - 5y
factorise : ab(x2 + y2) - xy (a2 + b2)
Factorise the following by taking out the common factors:
p(p2 + q2 - r2) + q(r2 - q2 -p2) - r(p2 + q2 - r2)
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
