Advertisements
Advertisements
Question
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Advertisements
Solution
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
= `(y^2 + 1/(4y^2) + 1) - (6y + 3/y)`
= `(y + 1/(2y))^2 - 6 (y + 1/(2y))`
= `(y + 1/(2y))(y + 1/(2y) - 6)`.
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
2y, 22xy
Factorise the following expression:
6p − 12q
Factorise the following expression:
− 4a2 + 4ab − 4 ca
Factorise.
15xy − 6x + 5y − 2
Factorize the following:
2x3y2 − 4x2y3 + 8xy4
Factorize the following:
10m3n2 + 15m4n − 20m2n3
Factorize the following:
x4y2 − x2y4 − x4y4
Factorize the following:
−4a2 + 4ab − 4ca
Factorise by taking out the common factors :
2 (2x - 5y) (3x + 4y) - 6 (2x - 5y) (x - y)
Factories by taking out common factors :
2x(a - b) + 3y(5a - 5b) + 4z(2b - 2a)
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise:
`x^4 + y^4 - 27x^2y^2`
Factorise : `x^2 + 1/x^2 - 3`
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Find the value of : `[(6.7)^2 - (3.3)^2]/[6.7 - 3.3]`
Factorise : a3 - a2 +a
Factorise : 3x2 + 6x3
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
Factorise:
a2 – ab(1 – b) – b3
factorise : xy2 + (x - 1) y - 1
factorise : ab(x2 + y2) - xy (a2 + b2)
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
Factorise:
5x2 - y2 - 4xy + 3x - 3y
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
