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Question
Factorise : `x^2 + 1/x^2 - 3`
Sum
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Solution
`x^2 + 1/x^2 - 3 `
= `x^2 + 1/x^2 - 2 xx x xx 1/x - 1`
= `( x - 1/x )^2 - 1`
= `( x - 1/x )^2 - (1)^2`
= `( x - 1/x - 1 )( x - 1/x + 1 )` [ ∵ a2 - b2 = ( a + b )( a - b )]
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