Advertisements
Advertisements
Question
Factorise the following expression:
20 l2m + 30 alm
Advertisements
Solution
20l2m = 2 × 2 × 5 × l × l × m
30alm = 2 × 3 × 5 × a × l × m
The common factors are 2, 5, l, and m.
∴ 20l2m + 30alm = (2 × 2 × 5 × l × l × m) + (2 × 3 × 5 × a × l × m)
= (2 × 5 × l × m) [(2 × l) + (3 × a)]
= 10lm (2l + 3a)
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
16x3, −4x2, 32x
Factorise the following expression:
ax2y + bxy2 + cxyz
Factorise.
x2 + xy + 8x + 8y
Factorize the following:
2l2mn - 3lm2n + 4lmn2
Factorise by taking out the common factors :
2 (2x - 5y) (3x + 4y) - 6 (2x - 5y) (x - y)
Factories by taking out common factors :
ab(a2 + b2 - c2) - bc(c2 - a2 - b2) + ca(a2 + b2 - c2)
factorise : 35a3b2c + 42ab2c2
factorise : x2y - xy2 + 5x - 5y
Factorise the following by taking out the common factors:
12a3 + 15a2b - 21ab2
Factorise the following by taking out the common factors:
p(p2 + q2 - r2) + q(r2 - q2 -p2) - r(p2 + q2 - r2)
