Advertisements
Advertisements
प्रश्न
Factorise the following expression:
20 l2m + 30 alm
Advertisements
उत्तर
20l2m = 2 × 2 × 5 × l × l × m
30alm = 2 × 3 × 5 × a × l × m
The common factors are 2, 5, l, and m.
∴ 20l2m + 30alm = (2 × 2 × 5 × l × l × m) + (2 × 3 × 5 × a × l × m)
= (2 × 5 × l × m) [(2 × l) + (3 × a)]
= 10lm (2l + 3a)
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
2y, 22xy
Factorise the following expression:
ax2y + bxy2 + cxyz
Factorise.
z − 7 + 7xy − xyz
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Find the value of : `[(18.5)^2 - (6.5)^2]/[18.5 + 6.5]`
Factorise : 3x5y - 27x4y2 + 12x3y3
Factorise : 2b (2a + b) - 3c (2a + b)
Factorise : (a+ 2b) (3a + b) - (a+ b) (a+ 2b) +(a+ 2b)2
Factorise the following by taking out the common factors:
4x2y3 - 6x3y2 - 12xy2
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
