Advertisements
Advertisements
Question
Factorise:
`"p"^2 + (1)/"p"^2 - 3`
Advertisements
Solution
`"p"^2 + (1)/"p"^2 - 3`
= `"P"^2 + (1)/"p"^2 - 2 - 1`
= `("p"^2 + (1)/"p"^2 - 2 xx "p" xx 1/"p") -1`
= `("p" - 1/"p")^2 - 1^2`
= `("p" - 1/"p" + 1)("p" - 1/"p" - 1)`.
APPEARS IN
RELATED QUESTIONS
Find the common factors of the terms.
14pq, 28p2q2
Find the common factors of the terms.
16x3, −4x2, 32x
Find the common factors of the terms.
10pq, 20qr, 30rp
Factorise the following expression:
6p − 12q
Factorise the following expression:
−16z + 20z3
Factorise the following expression:
− 4a2 + 4ab − 4 ca
Factorise the following expression:
ax2y + bxy2 + cxyz
Factorise.
15pq + 15 + 9q + 25p
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Factorize the following:
−4a2 + 4ab − 4ca
Factorise : `(9a)^2 + 1/(9a)^2 - 2 - 12a + 4/(3a)`
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise: x4 + y4 - 3x2y2
Factorise : 12(3x - 2y)2 - 3x + 2y - 1
Factorise : 3 - 5x + 5y - 12(x - y)2
Find the value of : `[(6.7)^2 - (3.3)^2]/[6.7 - 3.3]`
Factorise : 3x2 + 6x3
Factorise : a3b - a2b2 - b3
Factorise : 2b (2a + b) - 3c (2a + b)
factorise : ab(x2 + y2) - xy (a2 + b2)
Factorise xy2 - xz2, Hence, find the value of :
40 x 5.52 - 40 x 4.52
Factorise: a4 - 625
Factorise the following by taking out the common factors:
12a3 + 15a2b - 21ab2
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise:
x4 + y4 - 6x2y2
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
