Advertisements
Advertisements
Question
Factorise the following:
27x3 – 8y3
Sum
Advertisements
Solution
27x3 – 8y3 = (3x)3 – (2y)3 ...[a3 – b3 = (a – b)(a2 + ab + b2)]
= (3x – 2y)[(3x)2 + 3x × 2y + (2y)3]
= (3x – 2y)(9x3 + 6xy + 4xy + 4y3)
shaalaa.com
Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.5 [Page 105]
APPEARS IN
RELATED QUESTIONS
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
27m3 − 216n3
Factorise:
343a3 − 512b3
Factorise:
64x3 − 729y3
Simplify:
(x + y)3 − (x − y)3
Simplify:
(a + b)3 − a3 − b3
Simplify:
p3 − (p + 1)3
