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Question
Factorise:
125y3 − 1
Sum
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Solution
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
125y3 − 1
= (5y)3 − (1)3
= (5y − 1)[(5y)2 + (1)2 + (5y) × (1)]
= (5y − 1)(25y2 + 1 + 5y)
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