Advertisements
Advertisements
Question
Factorise:
x3 − 64y3
Sum
Advertisements
Solution
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
x3 − 64y3
= (x) − (4y)3
= (x − 4y)[(x)2 + (4xy) + (4y)2]
= (x − 4y)(x2 + 4xy + 16y2)
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
343a3 − 512b3
Factorise:
`16a^3 - 128/b^3`
Simplify:
(a + b)3 − a3 − b3
Simplify:
p3 − (p + 1)3
Factorise: x3 - 8y3
Factorise: `a^3 - 1/(a^3)`
Simplify: (a - b)3 - (a3 - b3)
