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प्रश्न
Factorise:
x3 − 64y3
योग
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
x3 − 64y3
= (x) − (4y)3
= (x − 4y)[(x)2 + (4xy) + (4y)2]
= (x − 4y)(x2 + 4xy + 16y2)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
125y3 − 1
Factorise:
64x3 − 729y3
Factorise:
`16a^3 - 128/b^3`
Simplify:
(x + y)3 − (x − y)3
Simplify:
(3a + 5b)3 − (3a − 5b)3
Factorise: 27p3 - 125q3.
Factorise the following:
a6 – 64
