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प्रश्न
Factorise:
y3 − 27
योग
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उत्तर
y3 − 27
y3 − 33
We know that,
a3 − b3 = (a − b) (a2 + ab + b2)
y3 − 33 = (y − 3) (y2 + y × 3 + 32)
= (y − 3) (y2 + 3y + 9)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]
Factorise:
8p3 −\[\frac{27}{p^3}\]
Factorise:
64x3 − 729y3
Simplify:
(x + y)3 − (x − y)3
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(a + b)3 − a3 − b3
Factorise: 27p3 - 125q3.
Factorise: 54p3 - 250q3.
Factorise the following:
a6 – 64
