Advertisements
Advertisements
प्रश्न
Factorise:
y3 − 27
योग
Advertisements
उत्तर
y3 − 27
y3 − 33
We know that,
a3 − b3 = (a − b) (a2 + ab + b2)
y3 − 33 = (y − 3) (y2 + y × 3 + 32)
= (y − 3) (y2 + 3y + 9)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
125y3 − 1
Factorise:
8p3 −\[\frac{27}{p^3}\]
Simplify:
(x + y)3 − (x − y)3
Simplify:
(3a + 5b)3 − (3a − 5b)3
Simplify:
(a + b)3 − a3 − b3
Simplify:
p3 − (p + 1)3
Factorise the following:
27x3 – 8y3
