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प्रश्न
Factorise:
343a3 − 512b3
योग
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
343a3 − 512b3
= (7a)3 − (8b)3
= (7a − 8b) {(7a)2 + (7a) × (8b) + (8b)2}
= (7a − 8b)(49a2 + 56ab + 64b2)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
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\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
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\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Factorise:
x3 − 64y3
Factorise:
125y3 − 1
Simplify:
(x + y)3 − (x − y)3
Simplify:
(3a + 5b)3 − (3a − 5b)3
Factorise: 27p3 - 125q3.
Factorise the following:
27x3 – 8y3
