Advertisements
Advertisements
प्रश्न
Factorise:
343a3 − 512b3
योग
Advertisements
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
343a3 − 512b3
= (7a)3 − (8b)3
= (7a − 8b) {(7a)2 + (7a) × (8b) + (8b)2}
= (7a − 8b)(49a2 + 56ab + 64b2)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Simplify:
\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
x3 − 64y3
Simplify: (a - b)3 - (a3 - b3)
Simplify: (2x + 3y)3 - (2x - 3y)3
Factorise the following:
27x3 – 8y3
Factorise the following:
a6 – 64
