Advertisements
Advertisements
प्रश्न
Factorise:
64x3 − 729y3
योग
Advertisements
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
64x3 − 729y3
= (4x)3 − (9y)3
= (4x − 9y){(4x)2 + (9y)2 + (4x) × (9y)}
= (4x − 9y)(16x2 + 81y2 + 36xy)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Factorise:
125y3 − 1
Simplify:
(3a + 5b)3 − (3a − 5b)3
Simplify:
p3 − (p + 1)3
Factorise: x3 - 8y3
Factorise: 54p3 - 250q3.
Factorise: `a^3 - 1/(a^3)`
Simplify: (a - b)3 - (a3 - b3)
