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प्रश्न
Factorise:
64x3 − 729y3
योग
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
64x3 − 729y3
= (4x)3 − (9y)3
= (4x − 9y){(4x)2 + (9y)2 + (4x) × (9y)}
= (4x − 9y)(16x2 + 81y2 + 36xy)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Factorise:
27m3 − 216n3
Factorise:
125y3 − 1
Factorise:
8p3 −\[\frac{27}{p^3}\]
Factorise:
`16a^3 - 128/b^3`
Simplify:
(x + y)3 − (x − y)3
Simplify:
(a + b)3 − a3 − b3
Simplify: (2x + 3y)3 - (2x - 3y)3
Factorise the following:
27x3 – 8y3
Factorise the following:
a6 – 64
