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प्रश्न
Factorise:
64x3 − 729y3
योग
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
64x3 − 729y3
= (4x)3 − (9y)3
= (4x − 9y){(4x)2 + (9y)2 + (4x) × (9y)}
= (4x − 9y)(16x2 + 81y2 + 36xy)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
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Factorise:
125y3 − 1
Factorise:
`16a^3 - 128/b^3`
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise: `a^3 - 1/(a^3)`
Simplify: (a - b)3 - (a3 - b3)
Simplify: (2x + 3y)3 - (2x - 3y)3
Factorise the following:
27x3 – 8y3
Factorise the following:
a6 – 64
