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प्रश्न
Factorise:
64x3 − 729y3
बेरीज
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
64x3 − 729y3
= (4x)3 − (9y)3
= (4x − 9y){(4x)2 + (9y)2 + (4x) × (9y)}
= (4x − 9y)(16x2 + 81y2 + 36xy)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{3 x^2 - x - 2}{x^2 - 7x + 12} \div \frac{3 x^2 - 7x - 6}{x^2 - 4}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
8p3 −\[\frac{27}{p^3}\]
Factorise:
`16a^3 - 128/b^3`
Simplify:
p3 − (p + 1)3
Factorise: 27p3 - 125q3.
Factorise: 54p3 - 250q3.
Simplify: (a - b)3 - (a3 - b3)
