Advertisements
Advertisements
प्रश्न
Factorise:
64x3 − 729y3
बेरीज
Advertisements
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
64x3 − 729y3
= (4x)3 − (9y)3
= (4x − 9y){(4x)2 + (9y)2 + (4x) × (9y)}
= (4x − 9y)(16x2 + 81y2 + 36xy)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]
Factorise:
x3 − 64y3
Factorise:
125y3 − 1
Simplify:
(3a + 5b)3 − (3a − 5b)3
Simplify:
p3 − (p + 1)3
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise the following:
27x3 – 8y3
