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प्रश्न
Factorise:
`16a^3 - 128/b^3`
बेरीज
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
`16a^3 - 128/b^3`
= `16[a^3 - 8/b^3]`
= `16[(a)^3 - (2/b)^3]`
= `16[(a - 2/b) {(a)^2 + (a) xx (2/b) + (2/b)^2}]`
= `16(a - 2/b) (a^2 + (2a)/b + 4/b^2)`
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Factorise:
27m3 − 216n3
Factorise:
125y3 − 1
Simplify:
(x + y)3 − (x − y)3
Simplify:
p3 − (p + 1)3
Factorise: x3 - 8y3
Factorise: 27p3 - 125q3.
Factorise: `a^3 - 1/(a^3)`
Simplify: (a - b)3 - (a3 - b3)
Factorise the following:
27x3 – 8y3
