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प्रश्न
Factorise:
125y3 − 1
बेरीज
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
125y3 − 1
= (5y)3 − (1)3
= (5y − 1)[(5y)2 + (1)2 + (5y) × (1)]
= (5y − 1)(25y2 + 1 + 5y)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
y3 − 27
Factorise:
x3 − 64y3
Factorise:
27m3 − 216n3
Simplify:
(x + y)3 − (x − y)3
Factorise: x3 - 8y3
Simplify: (a - b)3 - (a3 - b3)
Factorise the following:
27x3 – 8y3
