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प्रश्न
Factorise the following:
a6 – 64
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उत्तर
a6 – 64 = a6 – 26
= (a2)3 – (22)3 ...[a3 – b3 = (a – b) + (a2 + ab + b2)]
= (a2 – 22) [(a2)2 + (a2) (22) + (22)2]
= (a + 2) (a – 2) (a4 + 4a2 + 16)
= (a + 2) (a – 2) [(a2)2 + 42 + 8a2 – 4a2]
= (a + 2) (a – 2) [(a2 + 4)2 – (2a)2] ......{a2 – b2 = (a + b) (a – b)}
= (a + 2) (a – 2) (a2 + 4 + 2a) (a2 + 4 – 2a)
= (a + 2) (a – 2) (a2 + 2a + 4) (a2 – 2a + 4)
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संबंधित प्रश्न
Simplify:
\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Factorise:
x3 − 64y3
Factorise:
8p3 −\[\frac{27}{p^3}\]
Factorise:
64x3 − 729y3
Simplify:
p3 − (p + 1)3
Factorise: 54p3 - 250q3.
Factorise: `a^3 - 1/(a^3)`
Simplify: (a - b)3 - (a3 - b3)
Simplify: (2x + 3y)3 - (2x - 3y)3
