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प्रश्न
Factorise the following:
27x3 – 8y3
बेरीज
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उत्तर
27x3 – 8y3 = (3x)3 – (2y)3 ...[a3 – b3 = (a – b)(a2 + ab + b2)]
= (3x – 2y)[(3x)2 + 3x × 2y + (2y)3]
= (3x – 2y)(9x3 + 6xy + 4xy + 4y3)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.5 [पृष्ठ १०५]
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संबंधित प्रश्न
Simplify:
\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
y3 − 27
Factorise:
125y3 − 1
Factorise:
64x3 − 729y3
Simplify:
(a + b)3 − a3 − b3
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise: 54p3 - 250q3.
Factorise: `a^3 - 1/(a^3)`
