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प्रश्न
Factorise the following:
27x3 – 8y3
बेरीज
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उत्तर
27x3 – 8y3 = (3x)3 – (2y)3 ...[a3 – b3 = (a – b)(a2 + ab + b2)]
= (3x – 2y)[(3x)2 + 3x × 2y + (2y)3]
= (3x – 2y)(9x3 + 6xy + 4xy + 4y3)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.5 [पृष्ठ १०५]
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संबंधित प्रश्न
Simplify:
\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]
Simplify:
\[\frac{3 x^2 - x - 2}{x^2 - 7x + 12} \div \frac{3 x^2 - 7x - 6}{x^2 - 4}\]
Factorise:
64x3 − 729y3
Factorise:
`16a^3 - 128/b^3`
Simplify:
(x + y)3 − (x − y)3
Simplify:
p3 − (p + 1)3
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise: x3 - 8y3
Factorise: 27p3 - 125q3.
Simplify: (a - b)3 - (a3 - b3)
