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प्रश्न
Factorise the following:
27x3 – 8y3
योग
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उत्तर
27x3 – 8y3 = (3x)3 – (2y)3 ...[a3 – b3 = (a – b)(a2 + ab + b2)]
= (3x – 2y)[(3x)2 + 3x × 2y + (2y)3]
= (3x – 2y)(9x3 + 6xy + 4xy + 4y3)
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अध्याय 3: Algebra - Exercise 3.5 [पृष्ठ १०५]
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