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प्रश्न
Factorise:
125y3 − 1
योग
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उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
125y3 − 1
= (5y)3 − (1)3
= (5y − 1)[(5y)2 + (1)2 + (5y) × (1)]
= (5y − 1)(25y2 + 1 + 5y)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
y3 − 27
Factorise:
343a3 − 512b3
Factorise:
64x3 − 729y3
Simplify:
(x + y)3 − (x − y)3
Simplify:
p3 − (p + 1)3
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise: x3 - 8y3
Factorise: 54p3 - 250q3.
Factorise the following:
27x3 – 8y3
