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प्रश्न
Factorise:
y3 − 27
बेरीज
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उत्तर
y3 − 27
y3 − 33
We know that,
a3 − b3 = (a − b) (a2 + ab + b2)
y3 − 33 = (y − 3) (y2 + y × 3 + 32)
= (y − 3) (y2 + 3y + 9)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
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\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]
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\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
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\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]
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`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
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64x3 − 729y3
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Factorise the following:
27x3 – 8y3
