Advertisements
Advertisements
प्रश्न
Factorise:
x3 − 64y3
बेरीज
Advertisements
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
x3 − 64y3
= (x) − (4y)3
= (x − 4y)[(x)2 + (4xy) + (4y)2]
= (x − 4y)(x2 + 4xy + 16y2)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]
Simplify:
\[\frac{3 x^2 - x - 2}{x^2 - 7x + 12} \div \frac{3 x^2 - 7x - 6}{x^2 - 4}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Simplify:
`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`
Factorise:
64x3 − 729y3
Simplify:
(3a + 5b)3 − (3a − 5b)3
Simplify:
(3xy − 2ab)3 − (3xy + 2ab)3
Factorise: x3 - 8y3
Simplify: (2x + 3y)3 - (2x - 3y)3
Factorise the following:
27x3 – 8y3
