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Maharashtra State BoardSSC (English Medium) 8th Standard

Simplify: (1โˆ’2โข๐‘ฅ+๐‘ฅ2)/(1โˆ’๐‘ฅ3) ร—(1+๐‘ฅ+๐‘ฅ2)/(1+๐‘ฅ) - Mathematics

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Question

Simplify:

`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`

Sum
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Solution

It is known that,

a2 − b= (a + b) (a − b)

a3 − b3 = (a − b)(a2 + ab + b2)

`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`

= `(1 - x - x + x^2)/((1)^3 - (x)^3) xx (1 + x + x^2)/(1 + x)`

= `(1(1 - x) - x(1 - x))/((1 - x){(1)^2 + (1) xx (x) + (x)^2}) xx ((1 + x + x^2))/(1 + x)`

= `((1 - x) (1 - x))/((1 - x) (1 + x + x^2)) xx ((1 + x + x^2))/((1 + x))`

= `(1 - x)/(1 + x)`

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Chapter 6: Factorisation of Algebraic expressions - Practice Set 6.4 [Page 33]

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Balbharati Mathematics [English] Standard 8 Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 8 | Page 33
Balbharati Mathematics Integrated [English] Standard 8 Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 1. (8) | Page 48
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