Advertisements
Advertisements
Question
Factorise the following:
1 – 64a3 – 12a + 48a2
Advertisements
Solution
1 – 64a3 – 12a + 48a2 = (1)3 – (4a)3 – 3 × 12 × 4a + 3 × 1 × (4a)2
= (1 – 4a)3 ...[Using identity, (a – b)3 = a3 – b3 – 3a2b + 3ab2]
= (1 – 4a)(1 – 4a)(1 – 4a)
APPEARS IN
RELATED QUESTIONS
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = 2x3 + x2 – 2x – 1, g(x) = x + 1
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2
Factorise:
12x2 – 7x + 1
Factorise:
x3 + 13x2 + 32x + 20
Factorise:
2y3 + y2 – 2y – 1
Find the factor of the polynomial given below.
12x2 + 61x + 77
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
Find the factor of the polynomial given below.
`1/2x^2 - 3x + 4`
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
Factorise:
a3 – 8b3 – 64c3 – 24abc
