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Question
Factorise the following:
1 – 64a3 – 12a + 48a2
Sum
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Solution
1 – 64a3 – 12a + 48a2 = (1)3 – (4a)3 – 3 × 12 × 4a + 3 × 1 × (4a)2
= (1 – 4a)3 ...[Using identity, (a – b)3 = a3 – b3 – 3a2b + 3ab2]
= (1 – 4a)(1 – 4a)(1 – 4a)
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Factorisation of Polynomials
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Chapter 2: Polynomials - Exercise 2.3 [Page 21]
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