Advertisements
Advertisements
Question
Find the value of m so that 2x – 1 be a factor of 8x4 + 4x3 – 16x2 + 10x + m.
Advertisements
Solution
Let p(x) = 8x4 + 4x3 – 16x2 + 10x + m
Since, 2x – 1 is a factor of p(x), then put `p(1/2) = 0`
∴ `8(1/2)^4 + 4(1/2)^3 - 16(1/2)^2 + 10(1/2) + m = 0`
⇒ `8 xx 1/16 + 4 xx 1/8 - 16 xx 1/4 + 10(1/2) + m = 0`
⇒ `1/2 + 1/2 - 4 + 5 + m = 0`
⇒ 1 + 1 + m = 0
∴ m = –2
Hence, the value of m is –2.
APPEARS IN
RELATED QUESTIONS
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = kx2 – 3x + k
Factorise:
2x2 + 7x + 3
Factorize the following polynomial.
(x – 5)2 – (5x – 25) – 24
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
Factorize the following polynomial.
(x – 3) (x – 4)2 (x – 5) – 6
Show that p – 1 is a factor of p10 – 1 and also of p11 – 1.
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Factorise:
`a^3 - 2sqrt(2)b^3`
Find the following product:
(2x – y + 3z)(4x2 + y2 + 9z2 + 2xy + 3yz – 6xz)
