Advertisements
Advertisements
Question
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Advertisements
Solution
Let p(x) = ax3 + x2 – 2x + 4a – 9
Since, x + 1 is a factor of p(x), then put p(–1) = 0
∴ a(–1)3 + (–1)2 – 2(–1) + 4a – 9 = 0
⇒ –a + 1 + 2 + 4a – 9 = 0
⇒ 3a – 6 = 0
⇒ 3a = 6
⇒ `a = 6/3 = 2`
Hence, the value of a is 2.
APPEARS IN
RELATED QUESTIONS
Factorise:
12x2 – 7x + 1
Factorise:
2x2 + 7x + 3
Factorise:
3x2 – x – 4
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Factorize the following polynomial.
(x2 – 2x + 3) (x2 – 2x + 5) – 35
Factorize the following polynomial.
(y + 2) (y – 3) (y + 8) (y + 3) + 56
Factorize the following polynomial.
(x – 3) (x – 4)2 (x – 5) – 6
The factorisation of 4x2 + 8x + 3 is ______.
Factorise:
`a^3 - 2sqrt(2)b^3`
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
