Advertisements
Advertisements
प्रश्न
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Advertisements
उत्तर
Let p(x) = ax3 + x2 – 2x + 4a – 9
Since, x + 1 is a factor of p(x), then put p(–1) = 0
∴ a(–1)3 + (–1)2 – 2(–1) + 4a – 9 = 0
⇒ –a + 1 + 2 + 4a – 9 = 0
⇒ 3a – 6 = 0
⇒ 3a = 6
⇒ `a = 6/3 = 2`
Hence, the value of a is 2.
APPEARS IN
संबंधित प्रश्न
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Factorise:
x3 – 2x2 – x + 2
Factorise:
x3 + 13x2 + 32x + 20
Determine the following polynomial has (x + 1) a factor:
x4 + x3 + x2 + x + 1
Determine the following polynomial has (x + 1) a factor:
`x^3-x^2-(2+sqrt2)x+sqrt2`
Find the factor of the polynomial given below.
3y2 – 2y – 1
Factorize the following polynomial.
(x2 – 2x + 3) (x2 – 2x + 5) – 35
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
