Advertisements
Advertisements
Question
Factorise:
1 + 64x3
Sum
Advertisements
Solution
1 + 64x3 = (1)3 + (4x)3
= (1 + 4x)[(1)2 – (1)(4x) + (4x)2] ...[Using identity, a3 – b3 = (a + b)(a2 – ab + b2)]
= (1 + 4x)(1 – 4x + 16x2)
shaalaa.com
Factorisation of Polynomials
Is there an error in this question or solution?
Chapter 2: Polynomials - Exercise 2.3 [Page 22]
APPEARS IN
RELATED QUESTIONS
Factorise:
x3 + 13x2 + 32x + 20
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
Factorize the following polynomial.
(x2 – x)2 – 8 (x2 – x) + 12
Factorize the following polynomial.
(y2 + 5y) (y2 + 5y – 2) – 24
Which of the following is a factor of (x + y)3 – (x3 + y3)?
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
Factorise:
6x2 + 7x – 3
Factorise:
84 – 2r – 2r2
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Without finding the cubes, factorise:
(x – 2y)3 + (2y – 3z)3 + (3z – x)3
