Advertisements
Advertisements
प्रश्न
Factorise:
1 + 64x3
बेरीज
Advertisements
उत्तर
1 + 64x3 = (1)3 + (4x)3
= (1 + 4x)[(1)2 – (1)(4x) + (4x)2] ...[Using identity, a3 – b3 = (a + b)(a2 – ab + b2)]
= (1 + 4x)(1 – 4x + 16x2)
shaalaa.com
Factorisation of Polynomials
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Polynomials - Exercise 2.3 [पृष्ठ २२]
APPEARS IN
संबंधित प्रश्न
Factorise:
2x2 + 7x + 3
Factorise:
x3 – 2x2 – x + 2
Factorise:
x3 – 3x2 – 9x – 5
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Find the factor of the polynomial given below.
2m2 + 5m – 3
Factorize the following polynomial.
(y2 + 5y) (y2 + 5y – 2) – 24
x + 1 is a factor of the polynomial ______.
Factorise the following:
9x2 – 12x + 4
Factorise the following:
1 – 64a3 – 12a + 48a2
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
