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प्रश्न
Factorise:
`a^3 - 2sqrt(2)b^3`
बेरीज
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उत्तर
`a^3 - 2sqrt(2)b^3 = (a)^3 - (sqrt(2)b)^3`
= `(a - sqrt(2)b)[a^2 + a(sqrt(2)b) + (sqrt(2)b)^2]` ...[Using identity, a3 – b3 = (a – b)(a2 + ab + b2)]
= `(a - sqrt(2)b)(a^2 + sqrt(2)ab + 2b^2)`
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Factorisation of Polynomials
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Polynomials - Exercise 2.3 [पृष्ठ २२]
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संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 − 4x2 + x + 6, g(x) = x − 3
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = x2 + x + k
Factorise:
12x2 – 7x + 1
Factorise:
6x2 + 5x – 6
Factorise:
2y3 + y2 – 2y – 1
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
Factorise:
x2 + 9x + 18
Factorise:
6x2 + 7x – 3
Factorise:
a3 – 8b3 – 64c3 – 24abc
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
