Advertisements
Advertisements
प्रश्न
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
बेरीज
Advertisements
उत्तर
Let p(x) = x3 – x2 + 11x + 69
We have to show that, x + 3 is a factor of p(x).
i.e., p(–3) = 0
Now, p(–3) = (–3)3 – (–3)2 + 11(–3) + 69
= –27 – 9 – 33 + 69
= – 69 + 69
= 0
Hence, (x + 3) is a factor of p(x).
shaalaa.com
Factorisation of Polynomials
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Polynomials - Exercise 2.3 [पृष्ठ २०]
APPEARS IN
संबंधित प्रश्न
Factorise:
12x2 – 7x + 1
Factorise:
6x2 + 5x – 6
Factorise:
x3 – 2x2 – x + 2
Factorise:
x3 + 13x2 + 32x + 20
Factorise:
2y3 + y2 – 2y – 1
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
Determine which of the following polynomials has x – 2 a factor:
3x2 + 6x – 24
Find the value of m so that 2x – 1 be a factor of 8x4 + 4x3 – 16x2 + 10x + m.
Factorise the following:
1 – 64a3 – 12a + 48a2
Find the following product:
(2x – y + 3z)(4x2 + y2 + 9z2 + 2xy + 3yz – 6xz)
