Advertisements
Advertisements
प्रश्न
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
Advertisements
उत्तर
Let p(x) = x3 – x2 + 11x + 69
We have to show that, x + 3 is a factor of p(x).
i.e., p(–3) = 0
Now, p(–3) = (–3)3 – (–3)2 + 11(–3) + 69
= –27 – 9 – 33 + 69
= – 69 + 69
= 0
Hence, (x + 3) is a factor of p(x).
APPEARS IN
संबंधित प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Factorise:
2x2 + 7x + 3
Factorise:
2y3 + y2 – 2y – 1
Determine the following polynomial has (x + 1) a factor:
`x^3-x^2-(2+sqrt2)x+sqrt2`
Find the factor of the polynomial given below.
2m2 + 5m – 3
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
Factorize the following polynomial.
(x – 3) (x – 4)2 (x – 5) – 6
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
Determine which of the following polynomials has x – 2 a factor:
3x2 + 6x – 24
