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प्रश्न
Factorise:
12x2 – 7x + 1
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उत्तर
We can find two numbers such that pq = 12 × 1 = 12 and p + q = −7.
They are p = −4 and q = −3.
Here, 12x2 − 7x + 1
= 12x2 − 4x − 3x + 1
= 4x (3x − 1) − 1 (3x − 1)
= (3x − 1) (4x − 1)
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संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = kx2 – 3x + k
Factorise:
x3 – 2x2 – x + 2
Factorize the following polynomial.
(x2 – x)2 – 8 (x2 – x) + 12
Factorize the following polynomial.
(y + 2) (y – 3) (y + 8) (y + 3) + 56
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
The factorisation of 4x2 + 8x + 3 is ______.
Which of the following is a factor of (x + y)3 – (x3 + y3)?
Factorise:
`a^3 - 2sqrt(2)b^3`
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
