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प्रश्न
Factorise:
12x2 – 7x + 1
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उत्तर
We can find two numbers such that pq = 12 × 1 = 12 and p + q = −7.
They are p = −4 and q = −3.
Here, 12x2 − 7x + 1
= 12x2 − 4x − 3x + 1
= 4x (3x − 1) − 1 (3x − 1)
= (3x − 1) (4x − 1)
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संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2
Factorise:
x3 – 3x2 – 9x – 5
Determine the following polynomial has (x + 1) a factor:
x4 + x3 + x2 + x + 1
Determine the following polynomial has (x + 1) a factor:
x4 + 3x3 + 3x2 + x + 1
Factorize the following polynomial.
(x2 – x)2 – 8 (x2 – x) + 12
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
Show that p – 1 is a factor of p10 – 1 and also of p11 – 1.
Factorise:
6x2 + 7x – 3
Factorise:
1 + 64x3
