Advertisements
Advertisements
प्रश्न
Factorise:
12x2 – 7x + 1
Advertisements
उत्तर
We can find two numbers such that pq = 12 × 1 = 12 and p + q = −7.
They are p = −4 and q = −3.
Here, 12x2 − 7x + 1
= 12x2 − 4x − 3x + 1
= 4x (3x − 1) − 1 (3x − 1)
= (3x − 1) (4x − 1)
APPEARS IN
संबंधित प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = 2x3 + x2 – 2x – 1, g(x) = x + 1
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Determine the following polynomial has (x + 1) a factor:
`x^3-x^2-(2+sqrt2)x+sqrt2`
Find the factor of the polynomial given below.
12x2 + 61x + 77
Find the factor of the polynomial given below.
`sqrt 3 x^2 + 4x + sqrt 3`
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
x + 1 is a factor of the polynomial ______.
Which of the following is a factor of (x + y)3 – (x3 + y3)?
Without finding the cubes, factorise:
(x – 2y)3 + (2y – 3z)3 + (3z – x)3
