Advertisements
Advertisements
प्रश्न
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Advertisements
उत्तर
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
p(x) = `2x^2+kx+sqrt2`
p(1) = 0
⇒ `2(1)^2 + k(1) + sqrt2 = 0`
⇒ `2 + k + sqrt2 = 0`
⇒ k = `-2 -sqrt2`
k = `-(2+sqrt2)`
Therefore, the value of k is `-(2+sqrt2)`.
APPEARS IN
संबंधित प्रश्न
Factorise:
6x2 + 5x – 6
Factorise:
x3 – 2x2 – x + 2
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Factorize the following polynomial.
(y + 2) (y – 3) (y + 8) (y + 3) + 56
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
One of the factors of (25x2 – 1) + (1 + 5x)2 is ______.
Factorise:
84 – 2r – 2r2
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Factorise:
1 + 64x3
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
