Advertisements
Advertisements
प्रश्न
Factorise:
12x2 – 7x + 1
योग
Advertisements
उत्तर
We can find two numbers such that pq = 12 × 1 = 12 and p + q = −7.
They are p = −4 and q = −3.
Here, 12x2 − 7x + 1
= 12x2 − 4x − 3x + 1
= 4x (3x − 1) − 1 (3x − 1)
= (3x − 1) (4x − 1)
shaalaa.com
Factorisation of Polynomials
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise:
3x2 – x – 4
Factorise:
x3 + 13x2 + 32x + 20
Determine the following polynomial has (x + 1) a factor:
x4 + 3x3 + 3x2 + x + 1
Factorize the following polynomial.
(x2 – x)2 – 8 (x2 – x) + 12
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise the following:
1 – 64a3 – 12a + 48a2
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Factorise:
1 + 64x3
Factorise:
`a^3 - 2sqrt(2)b^3`
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
