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प्रश्न
Factorise:
12x2 – 7x + 1
योग
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उत्तर
We can find two numbers such that pq = 12 × 1 = 12 and p + q = −7.
They are p = −4 and q = −3.
Here, 12x2 − 7x + 1
= 12x2 − 4x − 3x + 1
= 4x (3x − 1) − 1 (3x − 1)
= (3x − 1) (4x − 1)
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