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प्रश्न
Factorise:
1 + 64x3
योग
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उत्तर
1 + 64x3 = (1)3 + (4x)3
= (1 + 4x)[(1)2 – (1)(4x) + (4x)2] ...[Using identity, a3 – b3 = (a + b)(a2 – ab + b2)]
= (1 + 4x)(1 – 4x + 16x2)
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Factorisation of Polynomials
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Polynomials - Exercise 2.3 [पृष्ठ २२]
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