Advertisements
Advertisements
प्रश्न
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = x2 + x + k
Find the value of k if x – 1 is a factor of x2 + x + k.
Advertisements
उत्तर
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
p(x) = x2 + x + k
p(1) = 0
⇒ (1)2 + 1 + k = 0
⇒ 2 + k = 0
⇒ k = −2
Therefore, the value of k is −2.
APPEARS IN
संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = 2x3 + x2 – 2x – 1, g(x) = x + 1
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 − 4x2 + x + 6, g(x) = x − 3
Factorise:
2x2 + 7x + 3
Factorize the following polynomial.
(x – 3) (x – 4)2 (x – 5) – 6
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
x + 1 is a factor of the polynomial ______.
The factorisation of 4x2 + 8x + 3 is ______.
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
