Advertisements
Advertisements
प्रश्न
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = x2 + x + k
Find the value of k if x – 1 is a factor of x2 + x + k.
Advertisements
उत्तर
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
p(x) = x2 + x + k
p(1) = 0
⇒ (1)2 + 1 + k = 0
⇒ 2 + k = 0
⇒ k = −2
Therefore, the value of k is −2.
APPEARS IN
संबंधित प्रश्न
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 − 4x2 + x + 6, g(x) = x − 3
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = kx2 – 3x + k
Factorise:
2y3 + y2 – 2y – 1
Determine the following polynomial has (x + 1) a factor:
x4 + 3x3 + 3x2 + x + 1
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Factorize the following polynomial.
(x2 – 6x)2 – 8 (x2 – 6x + 8) – 64
One of the factors of (25x2 – 1) + (1 + 5x)2 is ______.
Factorise the following:
9x2 – 12x + 3
Without finding the cubes, factorise:
(x – 2y)3 + (2y – 3z)3 + (3z – x)3
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
